Inspired by the movies I watch, the pictures I take, or the music I hear...
x = 2x(x-1) = 2(x-1)x²-x = 2x-2x²-2x = x-2x(x-2) = x-2x = 1
not exactly the answer i was looking for... there's a clearer explanation
x(x-1) = 2(x-1)x^2 - x = 2x - 1x^2 - x - 2x = -1-x^2 + 3x = 1-x (x-3) = 1evaluate: x = 2-(2)(2-3) = (-4)+6 = 22 =\= 1technically, you never said x=2 is the condition for which this equation exists, so x=2 is just some random thing completely unrelated. cookie!!!!!
dood... you guys BOTH suck... go back to math class...by multiplying both sides by (x-1) you turn the statement into a quadratic, and what do all quadratics have? 2 roots... so re-evaluate it and you will get the quadratic:x² - 3x + 2 = 0(x - 2)(x - 1) = 0therefore: x = 2, and x = 1 to satisfy the equation...*eats the cookie right in front of lorrie and trev*
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3 comments:
not exactly the answer i was looking for...
there's a clearer explanation
x(x-1) = 2(x-1)
x^2 - x = 2x - 1
x^2 - x - 2x = -1
-x^2 + 3x = 1
-x (x-3) = 1
evaluate: x = 2
-(2)(2-3) = (-4)+6 = 2
2 =\= 1
technically, you never said x=2 is the condition for which this equation exists, so x=2 is just some random thing completely unrelated.
cookie!!!!!
dood... you guys BOTH suck... go back to math class...
by multiplying both sides by (x-1) you turn the statement into a quadratic, and what do all quadratics have? 2 roots...
so re-evaluate it and you will get the quadratic:
x² - 3x + 2 = 0
(x - 2)(x - 1) = 0
therefore: x = 2, and x = 1 to satisfy the equation...
*eats the cookie right in front of lorrie and trev*
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